using numbers 1 to 9 only once to equal 1 million
Using digits 1,2,3,4,5,6,7,8,9 only once how do you equal 1 million.
Adding, multiplication, subtraction and division
$\endgroup$ 65 Answers
$\begingroup$Assuming you can construct number from digits one way to do it the following $$625*4*8(19*3-7)=5^42^22^3(57-7)=5^42^5*50=5^4*2^5*5^2*2=10^6$$
$\endgroup$ 4 $\begingroup$Without some more options of operations, I don't think you can get there, as $9!=362880$. Powers would make it easy: $(1+9)^{(2*3+4+5+6-7-8)}=(1+2*3+4+5-7-8+9)^6$
$\endgroup$ 3 $\begingroup$As Ross Millikan notes, this can't be done using each digit as a complete number, so I assume that building numbers from the digits is allowed.
For example: $(7814\times2-3)\times(69-5)=1000000$
$\endgroup$ $\begingroup$Also assuming powers: $((-1\times3+6\times9+7-8)\times4\times5)^2$
Actually $1 + 2 + 3 + 4 + 5*6 + 7 + 8 + 9 = 64 = 1000000_2$
$\endgroup$ 4 $\begingroup$$$(1+2+3+4)^6 \times (7-5-9+8) = 10^6 \times 1 = 1000000.$$
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