Simplify boolean expression to minimum number of literals
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Problem is to simplify this boolean expression:
$(a+b+c')(a'b'+c)$
I expanded it out and simplified to get to $a'b'c' + c(a+b)$ but that doesn't reduce the number of literals. Tried everything I could think of but I must be missing something...
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$\begingroup$How is this?
Found using Logic Friday 1.
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