Celeb Glow
news | April 04, 2026

Proof of divergence theorem

$\begingroup$

I am trying to proof the classical Gauss's divergence theorem given by,

For a bounded domain $D\in \mathbb{R}^N$ with a smooth boundary $\partial D$. For the function $F=(F_1,F_2,...,F_N)$ it is given by

$\int_{D}div(F)dx=\int_{\partial D}F\cdot v dS_x$, where $S$ is the surface of $D$ and $v$ denotes the surface normal vector.

I have proven this for $N=1$ by

$\int_{a}^bf'(x)dx=1\cdot f(b)+(-1)\cdot f(a)$ for any $(a,b)\in \mathbb{R}$, i.e. $F(x)=f(x)$ and $div(F)=f'(x)$.

But for general $N\in \mathbb{N}$, any hints?

$\endgroup$ 1 Reset to default

Know someone who can answer? Share a link to this question via email, Twitter, or Facebook.

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy