Celeb Glow
updates | April 07, 2026

How to plot $x^{2}=y^{2}-z^{2}$?

$\begingroup$

I have plotted this equation $x^{2}=y^{2}-z^{2}$ using Wolfram|Alpha and I got this graph:

x^{2}=y^{2}-z^{2}

I have made these changes to the equation:

First equation solution:

$y=-\sqrt{y^{2}-x^{2}}$

-\sqrt{y^{2}-x^{2}}

Second equation solution:

$y=\sqrt{y^{2}-x^{2}}$

\sqrt{y^{2}-x^{2}}

I want to make this by hand. How do I can do it? Which coordinate system I need to use to graph it?

$\endgroup$ 1

3 Answers

$\begingroup$

Write it as $x^2 + z^2 = y^2$. Note that y is the hypotenuse of a triangle with length x and height z. So, this forms a circular cone opening as you increase in y or decrease in y.

$\endgroup$ $\begingroup$

This figure is the (double) cone of equation $x^2=y^2-z^2$.

The gray plane is the plane $(x,y)$.

You can see that it is a cone noting that for any $y=a$ the projection of the surface on the plane $(x,z)$ is a circumference of radius $a$ with equation $z^2+x^2=a^2$.

Note that $z=\sqrt{y^2-x^2}$ is the semi-cone with $z>0$, i.e. above the plane $(x,y)$ and $z=-\sqrt{y^2-x^2}$ is the semi-cone below this plane.enter image description here

$\endgroup$ $\begingroup$

y^2 = x^2 + z^2 has the form of an equation for a circle. So, you are stacking, in the y direction, circles of increasing radius, one on top of the other.

$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy