How to plot $x^{2}=y^{2}-z^{2}$?
I have plotted this equation $x^{2}=y^{2}-z^{2}$ using Wolfram|Alpha and I got this graph:
I have made these changes to the equation:
First equation solution:
$y=-\sqrt{y^{2}-x^{2}}$
Second equation solution:
$y=\sqrt{y^{2}-x^{2}}$
I want to make this by hand. How do I can do it? Which coordinate system I need to use to graph it?
$\endgroup$ 13 Answers
$\begingroup$Write it as $x^2 + z^2 = y^2$. Note that y is the hypotenuse of a triangle with length x and height z. So, this forms a circular cone opening as you increase in y or decrease in y.
$\endgroup$ $\begingroup$This figure is the (double) cone of equation $x^2=y^2-z^2$.
The gray plane is the plane $(x,y)$.
You can see that it is a cone noting that for any $y=a$ the projection of the surface on the plane $(x,z)$ is a circumference of radius $a$ with equation $z^2+x^2=a^2$.
Note that $z=\sqrt{y^2-x^2}$ is the semi-cone with $z>0$, i.e. above the plane $(x,y)$ and $z=-\sqrt{y^2-x^2}$ is the semi-cone below this plane.
y^2 = x^2 + z^2 has the form of an equation for a circle. So, you are stacking, in the y direction, circles of increasing radius, one on top of the other.
$\endgroup$