Celeb Glow
general | April 06, 2026

How do you determine whether a curve uses arc length as a parameter?

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I know how to find arc length because it's simply a matter of plugging in values into a formula:

s(t) = $\int_a^t |v(u)|\,du$

But given an equation r(t), how do I show whether or not the curves use arc length as a parameter? e.g) $r(t) = <2 \cos{t}, 2 \sin{t}>$ for $0 \leq t \leq 2\pi$

I did some calculating and figured this much out:

$$v(t) = \left< -2\sin{t}, 2\cos{t}\right >$$

$$|v(t)| = 2$$

$$s(t) = 2t$$

Any examples or tips?

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1 Answer

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A parametrized $r(t)$ is parametrized by arclength when $t=s(t)$, where the arclength $s(t)$ is given by $$ \int_{t_0}^t\|r'(t)\|dt $$ In your example you found that $$ s(t)=2t $$ Since $t\neq 2t$, we can conclude that $r$ is not parametrized by arclength.

If, on the other hand, you were given $$ r(t)=\left\langle -2\sin\frac t2, 2\cos \frac t2 \right\rangle $$ You would find $$ \|r'(t)\|=1\implies s(t)=t $$ Which would mean that $r$ is parametrized by arclength.

As you can see, this also means that $r$ is parametrized by arclength whenever $\|r'(t)\|=1$ for all $t$.

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