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updates | April 13, 2026

How do you define a space of a cone in linear algebra?

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Let A be a $m \times r$ matrix, the cone generated by its columns is:

$$ C_{A} = \{ Ax \mid x \geq 0\} \subseteq \mathbb{R}^m$$

My question is, why is the word cone used to define this? I tried an example in $\mathbb{R}^2$ to get an intuition of this and it made sense to me, because if we only have two independent vectors in $\mathbb{R}^2$ then we basically cover a triangle (which I guess is the equivalent of a cone in 2D?).

Anyway, in 3D it made less sense to me because I expected a circular cone to be covered, but it seemed more like a 3D pyramid. Is that correct? Or maybe what I need is a rigorous definition of a cone and see if $C_{A}$ satisfies that definition. Does someone have an idea of why the word cone was used and how to justify it? Either rigorously or intuitively?


Edit:

after some googling it seems thats the definition of cone in linear algebra is:

In linear algebra, a (linear) cone is a subset of a vector space that is closed under multiplication by positive scalars

Kind of a unsatisfying definition because it didn't really look like a cone in $\mathbb{R}^3$, more like a triangular based pyramid (if we have the rank of A to be 3). Am I wrong? Or why is that called a cone?

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