Celeb Glow
general | April 20, 2026

Function of at most polynomial growth and its derivative

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I consider a function $f:\mathbb{R}^{+} \rightarrow \mathbb{R}$ which is continuous and differentiable.

I know moreover that both $f$ and $f'$ are of at most polynomial growth, i.e. I use the following definition:

The function $g$ is of at most polynomial growth if there exist constants $m$ and $C$ such that$$ |g(x)|\leq C (x^{-m} + x^m) $$for all $x \in \mathbb{R}^{+}$.

My question is:

Is there any relation in the degree of polynomial $m$ occuring in the above equation for $f$ and $f'$ if we know that that both are of at most polynomial growth?

My intuition is that if $f$ is bounded by a polynomial of degree $m$, then $f'$ is bounded by a polynomial of degree $m-1$.

Is this statement true?

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1 Answer

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Your statement will only be true when $f(x)$ is a strictly polynomial function. This is not hard to prove using the Power rule of differentiation.

However, it's not true for other non-strictly polynomial functions. We can disprove this extension by taking a simple counterexample. As rightly pointed out by someone in the comments, $f(x) = \sin (e^x)$ is a great counterexample.

Even though $f(x)$ is bounded by polynomial functions, such as $x,x^2,x^3$, etc., $f'(x)=e^x\cdot \cos x$ is obviously not, as the latter has exponential growth, which is always asymptotically greater than any polynomial function.

For further reading, check out the general trends in Big O notation, which is a key tool in algorithm efficiency analysis in computer science.

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