Formula for the nth term of a sequence

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I need to find a formula for the nth term in the sequence

$\frac{2}{3}, \frac{3}{5}, \frac{4}{7}, \frac{5}{9}, \frac{6}{11}$

I have tried the usual approach to find a formula. I first assumed that it was a geometric sequence, but it does not have a common ratio. It is also not an arithmetic sequence. I am at a complete loss on how to find a formula for this.

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2 Answers

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$T_n=\frac{n+1}{2n+1}$ should be able to work out from the pattern for $n\in\mathbb{N}$

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HINT:

Numerator are integers beginning at 2. Denominator are odd numbers beginning at 3

1st term numerator--->2

2nd term numerator--->3

3rd term numerator--->4

Can you guess what would be the $n^{th}$ term numerator?

1st term denominator is 3=2*1+1

2nd term denominator is 5=2*2+1

3rd term denominator is 7=2*3+1

Can you guess what would be the $n^{th}$ term denominator?

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