Celeb Glow
news | April 09, 2026

Formula for the general term of the Taylor series of $\tan(x)$ at $x = 0$

$\begingroup$

Today we were taught different expansions; one of them was the series expansion of $\tan(x)$, $$\tan(x)=x+\frac{x^3}{3}+\frac{2x^5}{15} + \cdots .$$ So, with curiosity, I asked my sir about next term. He said to get general formula divide series expansion of $\sin x,\cos x$. His reply didn't satisfy me. Do we have a general term for this expansion in elementary functions? If not, then why?

$\endgroup$ 2

1 Answer

$\begingroup$

We can write it using the Bernoulli numbers $B_n$: $$\tan x \sim \sum_{k = 1}^{\infty} \frac{(-1)^{k - 1} 4^k (4^k - 1) B_{2k}}{(2 k)!} x^{2 k - 1}.$$ The radius of convergence is $\frac{\pi}{2}$. (As one might guess, the series for $\tanh$ is the same, with the sign correction term $(-1)^{k - 1}$ removed.)

One can also produce terms in the expansion of this series using the well-known series for $\arctan$ and solving term-by-term.

$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy