Convert all files in directory using FFMPEG
I'm trying to write a script to convert all the files in a directory to m4v, whilst trying to keep similar (if not the same) quality and compress the file to reduce the overall size.
I've pieced together a small batch script but it won't run. Can anyone lend a hand/suggest how best to compress and retain quality?
#!/bin/bash
#Convert files using ffmpeg
DIR="/Volumes/Misc/To Convert 2"
for i in $DIR; do ffmpeg -i "$i" -c:v libx264 -crf 19 -preset slow -c:a aac -strict experimental -b:a 192k -ac 2 "/Volumes/Misc/Converted/${i%.*}.m4v"
doneEDIT: OUTPUTThis is the output that I get when I try to run the shell script
ffmpeg version 2.6.1-tessus Copyright (c) 2000-2015 the FFmpeg developers built with Apple LLVM version 6.0 (clang-600.0.57) (based on LLVM 3.5svn) configuration: --cc=/usr/bin/clang --prefix=/Users/tessus/data/ext/ffmpeg/sw --as=yasm --extra-version=tessus --disable-shared --enable-static --disable-ffplay --enable-gpl --enable-pthreads --enable-postproc --enable-libmp3lame --enable-libtheora --enable-libvorbis --enable-libx264 --enable-libx265 --enable-libxvid --enable-libspeex --enable-bzlib --enable-zlib --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libxavs --enable-libsoxr --enable-libwavpack --enable-version3 --enable-libvo-aacenc --enable-libvo-amrwbenc --enable-libvpx --enable-libgsm --enable-libopus --enable-libmodplug --enable-fontconfig --enable-libfreetype --enable-libass --enable-libbluray --enable-filters --disable-indev=qtkit --disable-indev=x11grab_xcb --enable-runtime-cpudetect libavutil 54. 20.100 / 54. 20.100 libavcodec 56. 26.100 / 56. 26.100 libavformat 56. 25.101 / 56. 25.101 libavdevice 56. 4.100 / 56. 4.100 libavfilter 5. 11.102 / 5. 11.102 libswscale 3. 1.101 / 3. 1.101 libswresample 1. 1.100 / 1. 1.100 libpostproc 53. 3.100 / 53. 3.100
/Volumes/Misc/ToConvert: Operation not permitted2 Answers
In general it is not safe to parse the output of ls(see below) and similarly "*.*".
I suggest to use find it protects you from unusual file name with special character.
#!/bin/bash
#Convert files using ffmpeg
OrDir="/Volumes/Misc/To Convert 2/"
find "$OrDir" -type f -exec /bin/bash -c \ 'f2=$(basename "$1"); \ ffmpeg -i "$1" -c:v libx264 -crf 19 -preset slow -c:a aac -strict experimental -b:a 192k -ac 2 "/Volumes/Misc/Converted/${f2%.*}.m4v" ' _ {} \;You can check it with a filename such as
cp myfile.mpg myfile$'\n'with_new_line.mpgReferences
- Why is it not safe or wise to parse the output of
ls?
There are a lot of references on internet.
You can have a quick understanding here.
You can read a lot more here
As the directory name contains spaces, you need to quote "$DIR" to prevent spaces from being parsed as word separators.
I would also suggest you slightly change the for loop:
#!/bin/bash
DIR="/Volumes/Misc/To Convert 2"
cd "$DIR"
for i in *.*; do ffmpeg -i "$i" -your_option "/Volumes/Misc/Converted/${i%.*}.m4v"
done
