Celeb Glow
updates | April 13, 2026

Composition of sets

$\begingroup$

Question: Let the set $A$ be defined as $A = \{ a, b, c, d \}$, and let the relations $R$ and $S$ on the set $A$ be defined as

$R = \{(d, a), (a, b), (b, c)\}$, and $S = \{(a, a), (b, d), (d, c)\}$.

Explain why the ordered pair $(a, b)$ is or is not an element of the composition of $S$ and $R$ (denoted $R \circ S$).

I would think $(a,b)$ is not in composition $R\circ S$ because there does not exist an element $x$ of $A$ such that $aSx$ and $xRa$.

Is my thinking correct? How else would you elaborate that it is or is not in composition $R\circ S$?

$\endgroup$

2 Answers

$\begingroup$

If $(a,b)$ is in $R\circ S$, then there is an $x\in A$, such that $aSx$ and $xRb$ (check if you have a typo in the last bit).

But there is such an $x$. I can take $x=a$. I have that $aSa$, and that $aRb$. Hence $a(R\circ S)b$.

$\endgroup$ $\begingroup$

You may think on $R\circ S$ as the relation "first $S$, then $R$". Now, $S$ sends $a$ to $a$ and $R$ sends $a$ to $b$. You can conclude the result now?

$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy