Celeb Glow
general | April 05, 2026

Bimorphism which is neither injective nor surjective

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In Ring the inclusion $f:\mathbb Z \to \mathbb Q$ is a not surjective but injective bimorphism.

In Div the quotient map $g:\mathbb Q \to \mathbb Q / \mathbb Z$ is a not injective but surjective bimorphism.

So the question arises: Is there an algebraic category with a bimorphism which is neither injective nor surjective?

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1 Answer

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Can't you just form the product category of the two examples you already gave?

I suggest this as a question, because I don't really know for certain that a pair of bimorphisms from the two categories is a bimorphism in the product category, but I suspect it is true. I also don't know if such a product is considered an "algebraic category."

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