Celeb Glow
general | April 05, 2026

Are curl and divergence local properties?

$\begingroup$

Example: curl is 0 and/or divergence is non-zero for a field. Does that mean that it has this property at some point in that field or all the points in that field?

Like, I am thinking of a simple electric field lines due to a stationary charge. The divergence is non-zero at the point where the charge is located but if we move sufficiently far away then the lines are basically parallel and we have a situation where divergence is almost zero.

$\endgroup$ 1

2 Answers

$\begingroup$

Classically both, as well as the gradient, are local operators. Applied to any smooth function they depend only on the values in the vicinity of a point. Generalizing to weak derivatives things are a bit different, with these derivatives being defined in terms of functionals, typically as integrations of test functions over a region with specific boundary behavior.

ADDED

But as you guess, and guess correctly you did, the classical derivative, curl, divergence can assign different values at different points.

$\endgroup$ $\begingroup$

The curl and divergence operators, $\nabla \times$ and $\nabla \cdot$, are operators which send scalar functions, say $f(x,y)$ to vector functions ($\nabla \times f)$ and scalar functions ($\nabla \cdot f$) respectively. So the curl and divergence are operators, which result in new functions, and therefore are global rather than local. So at two points in the field $f$, the divergence and curl will generally take two different values.

$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy